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Design efficient continuous coding 27112023.ngd 1.25 KiB
Design Choice situation opt1.cow opt1.adv opt1.vet opt1.far opt1.met opt1.bon opt2.cow opt2.adv opt2.vet opt2.far opt2.met opt2.bon Block
1 1 1 1 1 1 1 1 1 0 0 0 3 7 2
1 2 1 1 1 0 2 6 0 0 1 1 2 1 2
1 3 0 1 0 1 3 0 0 0 1 0 0 4 2
1 4 1 0 1 0 1 2 1 1 0 1 2 7 1
1 5 0 0 0 0 1 3 1 1 0 1 3 2 2
1 6 1 1 1 1 0 5 0 0 1 0 4 3 1
1 7 0 1 0 1 4 2 1 0 1 0 0 6 1
1 8 0 0 0 0 2 7 0 1 1 1 2 0 2
1 9 0 0 1 1 3 6 1 1 0 0 1 2 2
1 10 1 0 0 0 4 3 0 1 1 1 0 6 1
1 11 1 0 0 1 0 4 0 1 0 0 4 5 1
1 12 1 1 0 0 0 4 1 0 1 1 4 4 2
1 13 0 1 1 0 3 5 1 0 0 1 1 3 1
1 14 0 1 1 0 2 0 0 0 0 1 1 0 1
1 15 0 0 0 1 0 7 1 1 1 0 3 1 1
1 16 1 0 1 1 4 1 0 1 0 0 0 5 2
||||||||||
design
;alts = opt1*, opt2*, opt3
;eff = (mnl, d)
;alg = swap
;rows = 16
;block = 2
;model:
U(opt1) = b1[0.2] * COW[0,1]
+ b2[0.2] * ADV[0,1]
+ b3[0.2] * VET[0,1]
+ b4[0.2] * FAR[0,1]
+ b5[0.1] * MET[0,1,2,3,4]
+ b6[0.2] * BON[0,1,2,3,4,5,6,7]
+ i1[0] * COW.dummy[0] * VET.dummy[1]
/
U(opt2) = b1 * COW
+ b2 * ADV
+ b3 * VET
+ b4 * FAR
+ b5 * MET
+ b6 * BON
+ i1 * COW.dummy[0] * VET.dummy[1]
/
U(opt3) = asc3[0.2]
;
$